To find the percentage of calcium carbonate in the tablet, we need to calculate the amount of calcium carbonate used in the neutralization reaction.
First, let's find the number of moles of H2SO4 used. We can do this using the equation:
moles of H2SO4 = Molarity of H2SO4 × Volume of H2SO4
In this case, the molarity of H2SO4 is 0.0956 M, and the volume used is 9.19 mL (which can be converted to liters by dividing by 1000):
moles of H2SO4 = 0.0956 M × (9.19 mL / 1000 mL/L)
Now, we can calculate the number of moles of calcium carbonate used in the reaction. According to the balanced chemical equation between calcium carbonate (CaCO3) and sulfuric acid (H2SO4), the molar ratio is 1:1. This means that for every mole of H2SO4, there is one mole of CaCO3.
moles of CaCO3 = moles of H2SO4
Next, we can calculate the mass of calcium carbonate used. The molar mass of CaCO3 can be calculated by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms.
molar mass of CaCO3 = (1 × atomic mass of Ca) + (1 × atomic mass of C) + (3 × atomic mass of O)
Now, we can calculate the mass of calcium carbonate:
mass of CaCO3 = moles of CaCO3 × molar mass of CaCO3
Finally, we can calculate the percentage of calcium carbonate in the tablet by dividing the mass of calcium carbonate by the mass of the tablet and multiplying by 100:
percentage of CaCO3 = (mass of CaCO3 / mass of tablet) × 100
Plugging in the given values, we can now calculate the percentage of calcium carbonate in the tablet.