Asked by Help!!
The antacid Amphogel contains aluminum hydroxide Al(OH}3
How many milliliters of 2.00(M}HCl are required to react with 80.0 mL of 1.48 (M} Al(OH)3(s)?
Al(OH)3(s)+ 3HCl(aq)to AlCl3(aq) + 3H2O(aq)
How many milliliters of 2.00(M}HCl are required to react with 80.0 mL of 1.48 (M} Al(OH)3(s)?
Al(OH)3(s)+ 3HCl(aq)to AlCl3(aq) + 3H2O(aq)
Answers
Answered by
DrBob222
Moles Al(OH)3 = M x L = ??
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles HCl.
Now M HCl = moles HCl/M HCl. Substitute and solve for L, then convert to mL.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles HCl.
Now M HCl = moles HCl/M HCl. Substitute and solve for L, then convert to mL.
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