Question

John walks 1.0 km north, turns and walks 1.2 km at 50 degrees north of due east, and then turns and walks .8 km at 25 degrees north of east. what is the resultant distance and direction he has flown
D = 1km[90o] + 1.2km[50o] + 0.8km[25o]

X=1*cos90 + 1.2cos50 + 0.8*cos25=1.50 km
Y=1*sin90+1.2*sin50+0.8*sin25=2.257 km

tanA = Y/X = 2.257/1.50 = 1.50892
A = 56.5o = Direction.

D = Y/sinA = 2.257/sin56.5=2.71m[56.5o].

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