Asked by Eva
John walks 1.0 km north, turns and walks 1.2 km at 50 degrees north of due east, and then turns and walks .8 km at 25 degrees north of east. what is the resultant distance and direction he has flown
Answers
Answered by
Henry
D = 1km[90o] + 1.2km[50o] + 0.8km[25o]
X=1*cos90 + 1.2cos50 + 0.8*cos25=1.50 km
Y=1*sin90+1.2*sin50+0.8*sin25=2.257 km
tanA = Y/X = 2.257/1.50 = 1.50892
A = 56.5o = Direction.
D = Y/sinA = 2.257/sin56.5=2.71m[56.5o].
X=1*cos90 + 1.2cos50 + 0.8*cos25=1.50 km
Y=1*sin90+1.2*sin50+0.8*sin25=2.257 km
tanA = Y/X = 2.257/1.50 = 1.50892
A = 56.5o = Direction.
D = Y/sinA = 2.257/sin56.5=2.71m[56.5o].
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