Asked by etulan
a man walks 8km north and 5km in a direction east of north.find the distance from the starting point
Answers
Answered by
Steve
8kmN moves (0,8)
5km NE moves (3.5,3.5)
add them up to get (3.5,11.5)
distance is thus √(3.5^2 + 11.5^2) = 12.0
5km NE moves (3.5,3.5)
add them up to get (3.5,11.5)
distance is thus √(3.5^2 + 11.5^2) = 12.0
Answered by
Anonymous
This is a pythagorean theorem problem:
a^2 + b^2 = c^2
You have two sides and you are going to solve for c.
a^2 + b^2 = c^2
You have two sides and you are going to solve for c.
Answered by
Ben
1. A man walks 10km east and 20km south the displacement of the man from initial position
2. In figure below R= 30, find x and Y respectively.
2. In figure below R= 30, find x and Y respectively.
Answered by
shehab
What is the length of the hypotenuse? If necessary, round to the nearest tenth.
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