Asked by etulan

a man walks 8km north and 5km in a direction east of north.find the distance from the starting point

Answers

Answered by Steve
8kmN moves (0,8)
5km NE moves (3.5,3.5)

add them up to get (3.5,11.5)

distance is thus √(3.5^2 + 11.5^2) = 12.0
Answered by Anonymous
This is a pythagorean theorem problem:

a^2 + b^2 = c^2

You have two sides and you are going to solve for c.
Answered by Ben
1. A man walks 10km east and 20km south the displacement of the man from initial position
2. In figure below R= 30, find x and Y respectively.
Answered by shehab
What is the length of the hypotenuse? If necessary, round to the nearest tenth.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions