Asked by Tam

Marit and jennifer had an equal number of crackers. Each day, Marit ate 12 crackers and Jennifer ate 6 more crackers than Marit. When Jennifer had 24 crackers left, Marit had 96 crackers left. How many crackers did each of them have at first?

Answers

Answered by Henry
Marit ate 12 crackers/day.
Jennifer ate 12+6 = 18 crackers/day.

Difference = 96-24 = 72 crackers

72Crackers/6Crackers/day = 12 Days

Marit=12crackers/day * 12Days=144 Crackers.

Jennifer=18crackers/day*12days=216 crackers.
Answered by Rosario
after n days:
M - 12n = 96
J - 18n = 24

Given M = J; they had same number of crackers

so M - 12n = 96
-M + 18n = -24

so 6n = 72 that is n = 12

M - 12 x 12 = 96
M = 240

J - 18 x 12 = 24
J - 216 = 24
J = 240

Answer: 240 both had 240 crackers to begin with.
Answered by Anonymous
so confusing
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