Asked by Tam
Marit and jennifer had an equal number of crackers. Each day, Marit ate 12 crackers and Jennifer ate 6 more crackers than Marit. When Jennifer had 24 crackers left, Marit had 96 crackers left. How many crackers did each of them have at first?
Answers
Answered by
Henry
Marit ate 12 crackers/day.
Jennifer ate 12+6 = 18 crackers/day.
Difference = 96-24 = 72 crackers
72Crackers/6Crackers/day = 12 Days
Marit=12crackers/day * 12Days=144 Crackers.
Jennifer=18crackers/day*12days=216 crackers.
Jennifer ate 12+6 = 18 crackers/day.
Difference = 96-24 = 72 crackers
72Crackers/6Crackers/day = 12 Days
Marit=12crackers/day * 12Days=144 Crackers.
Jennifer=18crackers/day*12days=216 crackers.
Answered by
Rosario
after n days:
M - 12n = 96
J - 18n = 24
Given M = J; they had same number of crackers
so M - 12n = 96
-M + 18n = -24
so 6n = 72 that is n = 12
M - 12 x 12 = 96
M = 240
J - 18 x 12 = 24
J - 216 = 24
J = 240
Answer: 240 both had 240 crackers to begin with.
M - 12n = 96
J - 18n = 24
Given M = J; they had same number of crackers
so M - 12n = 96
-M + 18n = -24
so 6n = 72 that is n = 12
M - 12 x 12 = 96
M = 240
J - 18 x 12 = 24
J - 216 = 24
J = 240
Answer: 240 both had 240 crackers to begin with.
Answered by
Anonymous
so confusing
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