Question
Jennifer got a box of chocolates. The box is a right triangular prism shaped box. It is 7 inches long, and the triangular base measures 2 inches x 3 inches x 4 inches. What is the surface area of the box of chocolates?
Answers
Steve
there are two ends and three lateral faces, so
2A + (2+3+4)*7
to find the area of the triangular bases, draw an altitude to the base of length 4. That line divides the base into two parts of length x and 4-x. Then, if the height is h,
h^2+x^2 = 4
h^2+(4-x)^2 = 9
x = 21/8
now find h, and
the area is (1/2)(4)(h)
2A + (2+3+4)*7
to find the area of the triangular bases, draw an altitude to the base of length 4. That line divides the base into two parts of length x and 4-x. Then, if the height is h,
h^2+x^2 = 4
h^2+(4-x)^2 = 9
x = 21/8
now find h, and
the area is (1/2)(4)(h)
Jordan
Steve I am confused sorry what is the actual answer?
Steve
guess you better ask "Kaydon"
gabe
68.8 inches squared
Anonymous
No
Anonymous
Asked someone else Telsa
Elliot
Be quiet
Elliot
hi