Jennifer had 3 times as much coffee powder as Mie at first. After Jennifer gave 16.77 kg of coffee powder to Mie, Jennifer had 77.5 kg more coffee powder than Mie. How much coffee powder did Mie have at first?

User Icon for Bosnian Bosnian answered
2 years ago

J = Jennifer's coffee powder at first

M = Mie's coffee powder at first

Jennifer had 3 times as much coffee powder as Mie at first, means:

J = 3 M

After Jennifer gives 16.77 kg to Mie Jennifer has J - 16.77 kg of coffee powder.

Mie has M + 16.77 kg of coffee powder.

Now Jennifer had 77.5 kg more coffee powder than Mie, this means:

J - 16.77 = M + 16.77 + 77.5

J - 16.77 = M + 94.27

Add 16.77 to both sides

J = M + 111.04

Replace J by 3M in this equation.

3 M = M + 111.04

Subtract M to both sides.

2 M = 111.04

M = 111.04 / 2

M = 55.52

At first Mie have 55.52 kg coffee powder.

Check result.

At first Jennifer have 3 M = 3 ∙ 55.52 = 166.56 kg coffee powder

After Jennifer gives 16.77 kg to Mie Jennifer has 166.56 - 16.77 = 149.79 kg of coffee powder.

Mie has 55.52 + 16.77 = 72.29 kg of coffee powder.

Jennifer's coffee powder - Mie's coffee powder = 149.79 - 72.29 = 77.5 kg

Jennifer had 77.5 kg more coffee powder than Mie.

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

Let's assume that Mie had x kg of coffee powder at first.

Jennifer had 3 times as much coffee powder as Mie, so Jennifer had 3x kg of coffee powder at first.

After Jennifer gave 16.77 kg of coffee powder to Mie, Jennifer had 3x - 16.77 kg of coffee powder.

Jennifer had 77.5 kg more coffee powder than Mie, so we can set up the following equation:

3x - 16.77 = x + 77.5

Simplifying the equation, we have:

2x = 94.27

Dividing both sides of the equation by 2, we find:

x = 47.135

Therefore, Mie had approximately 47.135 kg of coffee powder at first.