Asked by Quince
1) A rectangle has perimeter 38 feet and an area of 78 square feet. Find the dimensions of the rectangle assuming the width is smaller than the length.
L= W=
2) A rectangular canvas picture measures 9 inches by 7 inches. The canvas is mounted inside a frame of uniform width, increasing the total area covered by both canvas and frame to 120 square inches. Find the uniform width of the frame.
L= W=
2) A rectangular canvas picture measures 9 inches by 7 inches. The canvas is mounted inside a frame of uniform width, increasing the total area covered by both canvas and frame to 120 square inches. Find the uniform width of the frame.
Answers
Answered by
Steve
LW = 78, so L = 78/W
L+W = 19
78/W + W = 19
W^2 - 19W + 78 = 0
W=6,L=13
for the picture, if the frame has width w, then
(7+2w)(9+2w) = 120
now just solve for w.
Just by looking, I'd say that 10x12 = 120, so w=1.5
L+W = 19
78/W + W = 19
W^2 - 19W + 78 = 0
W=6,L=13
for the picture, if the frame has width w, then
(7+2w)(9+2w) = 120
now just solve for w.
Just by looking, I'd say that 10x12 = 120, so w=1.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.