Question

The perimeter of a rectangle is 53 meters. The length is 2.3 meters longer than the width, w. Write and solve an equation to find the width of the rectangle.
Can someone show and explain how to solve this step by step? Trying to get some late math done. v.v
perimeter is two lengths plus two widths ... P = 2 L + 2 W

The length is 2.3 meters longer than the width ... L = W + 2.3
...substitute for the length

53 = 2 (W + 2.3) + 2 W = 4 W + 4.6

solve for W , then substitute back to find L
4.6?

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