Asked by payalsun
the perimeter of the rectangle ABCD is 30 cm. Alisa cuts 3 rectangles from that rectangle. the sum of the three perimeter is 20. what is the perimeter of the figure obtained after the cutting
Answers
Answered by
oobleck
I'll assume that all 3 small rectangles are cut from the same end of the larger rectangle.
If y is the height of the large rectangle, then the three small rectangles have total perimeter of 6y+x, where x is the sum of their widths.
If the width of the larger rectangle is w, then
2(w+y) = 30
w+y = 15
Now, 2x+6y = 20
x = 10-3y = 10-3(15-w) = 3w-45
The perimeter of the figure after cutting is p=30-(x+y)
So, consider the possibilities.
y=1 (big rectangle is 14x1) x=7 so p=30-8=22
y=2, x=4, 24
and so on
Maybe there is more to the problem than you gave.
If y is the height of the large rectangle, then the three small rectangles have total perimeter of 6y+x, where x is the sum of their widths.
If the width of the larger rectangle is w, then
2(w+y) = 30
w+y = 15
Now, 2x+6y = 20
x = 10-3y = 10-3(15-w) = 3w-45
The perimeter of the figure after cutting is p=30-(x+y)
So, consider the possibilities.
y=1 (big rectangle is 14x1) x=7 so p=30-8=22
y=2, x=4, 24
and so on
Maybe there is more to the problem than you gave.
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