Asked by danielle
Calculate the molarity of a solution prepared by dissolving 16 g of urea,
NH2CONH2, in 39 g of H2O. The density of the solution is 1.3 g/mL.
I've tried this question so many times but I keep getting it wrong please help me
NH2CONH2, in 39 g of H2O. The density of the solution is 1.3 g/mL.
I've tried this question so many times but I keep getting it wrong please help me
Answers
Answered by
DrBob222
mols urea = grams/molar mass = 16/60.06 = 0.266 mols.
M = mols/L soln
mass solution is 16g + 39 g = 55g
volume = mass/density = 55/1.3 = about 42.3 cc
M = 0.266/0.0423 = about 6.3M
I rounded here and there. You should go through it and do it more accurately.
M = mols/L soln
mass solution is 16g + 39 g = 55g
volume = mass/density = 55/1.3 = about 42.3 cc
M = 0.266/0.0423 = about 6.3M
I rounded here and there. You should go through it and do it more accurately.
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