Asked by Jamal
Calculate the molarity (M) of a solution of the strong base Ca(OH)2 if the pOH is 0.650.
pOH= 0.650
pH = 14-0.650
pJ=13.35
-log(13.35) = -1.13
pOH= 0.650
pH = 14-0.650
pJ=13.35
-log(13.35) = -1.13
Answers
Answered by
DrBob222
pOH = 0.650
-0.650 = log(OH^-)
(OH^-) = 4.47 M
Ca(OH)2 = 1/2 that or 2.23 M
-0.650 = log(OH^-)
(OH^-) = 4.47 M
Ca(OH)2 = 1/2 that or 2.23 M
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