Asked by Jamal
                Calculate the molarity (M) of a solution of the strong base Ca(OH)2 if the pOH is 0.650.
 
pOH= 0.650
pH = 14-0.650
pJ=13.35
-log(13.35) = -1.13
            
        pOH= 0.650
pH = 14-0.650
pJ=13.35
-log(13.35) = -1.13
Answers
                    Answered by
            DrBob222
            
    pOH = 0.650
-0.650 = log(OH^-)
(OH^-) = 4.47 M
Ca(OH)2 = 1/2 that or 2.23 M
    
-0.650 = log(OH^-)
(OH^-) = 4.47 M
Ca(OH)2 = 1/2 that or 2.23 M
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