Asked by anon
Calculate the molarity of a Ba(OH)2 solution if 1.90 L is completely neutralized by 0.261 L of 0.505 M HNO3.
Answers
Answered by
DrBob222
2HNO3 + Ba(OH)2 ==> Ba(NO3)2 + 2H2O
mols HNO3 = M x L = 0.505 x 0.261 = ?
From the coefficients in the balanced equation 2 mol HNO3 = 1 mol Ba(OH)2; therefore mols Ba(OH)2 = 1/2 mol HNO3
Then M Ba(OH)2 = mols Ba(OH)2/L Ba(OH)2 = ?
Post your work if you get stuck.
mols HNO3 = M x L = 0.505 x 0.261 = ?
From the coefficients in the balanced equation 2 mol HNO3 = 1 mol Ba(OH)2; therefore mols Ba(OH)2 = 1/2 mol HNO3
Then M Ba(OH)2 = mols Ba(OH)2/L Ba(OH)2 = ?
Post your work if you get stuck.
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