Question
K2SO4+ Na2HPO4=?
NaHCO3 + Sr(NO3)2=?
NaHCO3 + Sr(NO3)2=?
Answers
DrBob222
I don't believe either of these react. In water they will dissolve to form the corresponding ions.
Graham
An ionic exchange reaction only occurs when dissolved ions are removed from solution as (1) a precipitate (solid), (2) a gas, or (3) form a molecule that remains in the liquid phase.
Sodium- and Potassium- -Biphosphates (and -Phosphates) are soluble. Sodium- and Potassium- -Sulfates (and -Bisulfates) are soluble. No reaction occurs.
However, Strontium Carbonate is insoluble.
NaHCO3(aq) + Sr(NO3)2(aq) = SrCO3(s) + NaNO3(aq) + HNO3(aq)
Sodium- and Potassium- -Biphosphates (and -Phosphates) are soluble. Sodium- and Potassium- -Sulfates (and -Bisulfates) are soluble. No reaction occurs.
However, Strontium Carbonate is insoluble.
NaHCO3(aq) + Sr(NO3)2(aq) = SrCO3(s) + NaNO3(aq) + HNO3(aq)
DrBob222
I agree that SrCO3 is insoluble; however, I believe the reaction (or lack of it) will form Sr(HCO3)2 and I believe that is soluble as is Ca(HCO3)2 and Ba(HCO3)2.
Ca(HCO3) can be formed by bubbling CO2 through a suspension of CaCO3.
Ba(HCO3)2 can be formed by bubbling CO2 through a (cold) suspension of BaCO3.
Therefore, I think Sr(HCO3)2 can be formed by bubbling CO2 through a cold suspension of SrCO3 and that Sr(HCO3)2 is soluble. However, I can't confirm that. I suspect in real life that no ppt will form (or perhaps a slight haze), then with standing the solution will lose CO2 and a ppt of SrCO3 will form.
Ca(HCO3) can be formed by bubbling CO2 through a suspension of CaCO3.
Ba(HCO3)2 can be formed by bubbling CO2 through a (cold) suspension of BaCO3.
Therefore, I think Sr(HCO3)2 can be formed by bubbling CO2 through a cold suspension of SrCO3 and that Sr(HCO3)2 is soluble. However, I can't confirm that. I suspect in real life that no ppt will form (or perhaps a slight haze), then with standing the solution will lose CO2 and a ppt of SrCO3 will form.