Asked by Michael
A 0.100 M solution of K2SO4 would contain the same total ion concentration as which of the following solutions?
A. 0.0800 M Na2CO3
B. 0.100 M NaCl
C. 0.0750 M Na3PO4
D. 0.0500 M NaOH
A. 0.0800 M Na2CO3
B. 0.100 M NaCl
C. 0.0750 M Na3PO4
D. 0.0500 M NaOH
Answers
Answered by
DrBob222
K2SO4 split when it ionizes as follows:
K2SO4(aq) ==> 2K^+ + SO4^2- or a total of three ions for each mol K2SO4. The concn in the problem for K2SO4 is 0.1 so the total concn of ions = 0.3M
Go through the answers and see which is larger.
Na2SO4 = 3 ions x 0.08 = 2.4M ions
NaCl = 2 ions x 0.1 = 0.2 M ion.
etc.
K2SO4(aq) ==> 2K^+ + SO4^2- or a total of three ions for each mol K2SO4. The concn in the problem for K2SO4 is 0.1 so the total concn of ions = 0.3M
Go through the answers and see which is larger.
Na2SO4 = 3 ions x 0.08 = 2.4M ions
NaCl = 2 ions x 0.1 = 0.2 M ion.
etc.
Answered by
suuny
8.471
Answered by
Anonymous
.0750
Answered by
ewewe
3ewe
Answered by
Alex
C. 0.0750 M Na3PO4.
You can trust me.
You can trust me.
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