Asked by mark
A 32.5 g sample of K2SO4 is dissolved in a quantity of water and stirred well. A 40.00 mL sample of the solution is evaporated to dryness and leaves behind 5.00 g of solid K2SO4.what is the molarity. Calculate molar masses of solutes to .01 grams
Answers
Answered by
DrBob222
mols K2SO4 in the 40 mL sample = g/molar mass = 5.00/molar mass K2SO4 = ?
Then M of the 40 mL sample is mols K2SO4/0.04 = ?
Then M of the 40 mL sample is mols K2SO4/0.04 = ?
Answered by
Ritul pegu
Septer 1 answer-
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