Question
the base of an isosceles triangle is 27dm.if the length of a leg is 11 more than one-third of the base,find the perimeter of the triangle?
Answers
Reiny
the base is 27 dm
each of the other legs is (1/3)(27) + 11 = 20 dm
So perimeter = 20+20+27 or 67 dm
each of the other legs is (1/3)(27) + 11 = 20 dm
So perimeter = 20+20+27 or 67 dm