Asked by SL
the base of an isosceles triangle is 18 centimeters long. The altitude to the base is 12 centimeters long. What is the approximate measure of a base angle of the triangle?
Answers
Answered by
drwls
Since it is isosceles, the altitude splits it into two congruent right triangles. The base angle is
arctan(12/9) = arctan(4/3). It's a "3,4,5" right triangle. Use a table or calculator to get the angle. It's about 53 degrees
arctan(12/9) = arctan(4/3). It's a "3,4,5" right triangle. Use a table or calculator to get the angle. It's about 53 degrees
Answered by
Henry
The altitude of an isosceles triangle
is the perpindicular bisector of the
base and devides the triangle into 2
congruent rt. triangles. Y=12=altitude, X=18/2=9= 1/2 of base.
TanB=Y/X=12/9=1.3333, B=53.13 Degrees.
is the perpindicular bisector of the
base and devides the triangle into 2
congruent rt. triangles. Y=12=altitude, X=18/2=9= 1/2 of base.
TanB=Y/X=12/9=1.3333, B=53.13 Degrees.
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