Asked by patrick
the base of an isosceles triangle is half as long as side of a square.Each of the legs of triangle is twice as long as a side of the square.How long is each side of the triangle if the sum of the perimeters is 34 m.
Answers
Answered by
Steve
base = s/2
leg = 2s
s/2 + 2*2s + 4s = 34
Now solve for s, and then the triangle's sides.
leg = 2s
s/2 + 2*2s + 4s = 34
Now solve for s, and then the triangle's sides.
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