Question
A farmer wishes to enclose a rectangular region with 196 meters of fencing in such a way that the length is twice the width and that the region is divided along its length into two equal parts. What is the length and width in meters?
Answers
Reiny
Did you make a sketch?
width = x
length = 2x
but you dividing the length in two, so all sides are x
Count the x's , we need 7x
7x = 196
x = 28
the large rectangle is 54m by 28m
I assumed that the dividing side is parallel to the width.
If your dividing line is parallel to the length, then I would
define the original width as 2x and the length as 4x (thus avoiding fractions)
Then I see 3(4x) + 4(x) = 196
16x = 196
x = 12.25
and the field was 24.5m by 49 m
width = x
length = 2x
but you dividing the length in two, so all sides are x
Count the x's , we need 7x
7x = 196
x = 28
the large rectangle is 54m by 28m
I assumed that the dividing side is parallel to the width.
If your dividing line is parallel to the length, then I would
define the original width as 2x and the length as 4x (thus avoiding fractions)
Then I see 3(4x) + 4(x) = 196
16x = 196
x = 12.25
and the field was 24.5m by 49 m