Asked by eddie

a farmer wishes to enclose a rectangular region with 210 meters of fencing in such a way that the length is twice the width and the region is divided into two equal parts. what length and width should be used?
Answered by Henry
Width = X-meters.
Length = 2X-metes.
Divider = 2X-meters.

2*x + 2*2x + 2x = 210m,
2x + 4x + 2x = 210,
8x = 210,

X = 26.25m. = Width.
2X = 2*26.25 = 52.5m. = Length.
2X = 52.5 = Divider.

Answered by Peanut
26.25 is the width and the length is 52.25
Answered by Anonymous
x=width(since the width has three sections, left side, middle and right side, it becomes 3x)
2x=length
so equation is:

2*2x(upper and lower lengths)+3x(left side, middle and right side)=210

2*2x+3x=210
4x+3x=210
7x=210
x=30
2x=60
so the length is 60m and the width is 30m.
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