Asked by Jerry
Solve the equation cos^2A = sin^2A + sinA when 0¨¬¡A¡360¨¬. Select all the solutions from the list below.
A. 330 degrees
B. 270 degrees
C. 150 degrees
D. 30 degrees
A. 330 degrees
B. 270 degrees
C. 150 degrees
D. 30 degrees
Answers
Answered by
Steve
since cos^2 = 1-sin^2,
1-sin^2A - sin^2A - sinA = 0
2sin^2A + sinA - 1 = 0
(2sinA-1)(sinA+1) = 0
sinA = 1/2 or -1
A = 30,150,270
1-sin^2A - sin^2A - sinA = 0
2sin^2A + sinA - 1 = 0
(2sinA-1)(sinA+1) = 0
sinA = 1/2 or -1
A = 30,150,270
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