Question
The specific heat of fat is 0.45 cal/(g) , and the density of fat is 0.94 g/cm^3 .
How much energy (in calories) is needed to heat 22 cm^3 of fat from room temperature (25 ^\circ {\rm C}) to its melting point (35 ^\circ {\rm C})?
How much energy (in calories) is needed to heat 22 cm^3 of fat from room temperature (25 ^\circ {\rm C}) to its melting point (35 ^\circ {\rm C})?
Answers
DrBob222
mass fat = volume x density
q in cal = mass fat x specific heat fat (in cal/g) x (Tfinal-Tinitial)\
q in cal = mass fat x specific heat fat (in cal/g) x (Tfinal-Tinitial)\