Asked by priya
Two resistors connected in series have an equivalent resistance of 783.4 Ω. When they are connected in parallel, their equivalent resistance is 171.3 Ω. Find the resistance of each resistor.
Ω (small resistance)
Ω (large resistance
Ω (small resistance)
Ω (large resistance
Answers
Answered by
Devron
Equation 1.)
R1+R2=783.4
Equation 2.)
R1*R2/(R1+R2)=Req=783.4
Substitute equation 1 into 2:
R1=783.4-R2
and
R1*R2/(R1+R2)=Req=171.3
(783.4-R2)*R2/783.4-R2+R2=171.3
R2^2-783.4R2=-1.342 x 10^5
R2^2 -783.4R2+1.342 x 10^5=0
(R2 -3.663 x 10^2)^2
R2=3.663 x 10^2 Ω
R1 + R2=783.4 Ω
R1=783.4 Ω-R2
R1=734.4Ω-3.663 x 10^2 Ω
R1=417.1 Ω
R1+R2=783.4
Equation 2.)
R1*R2/(R1+R2)=Req=783.4
Substitute equation 1 into 2:
R1=783.4-R2
and
R1*R2/(R1+R2)=Req=171.3
(783.4-R2)*R2/783.4-R2+R2=171.3
R2^2-783.4R2=-1.342 x 10^5
R2^2 -783.4R2+1.342 x 10^5=0
(R2 -3.663 x 10^2)^2
R2=3.663 x 10^2 Ω
R1 + R2=783.4 Ω
R1=783.4 Ω-R2
R1=734.4Ω-3.663 x 10^2 Ω
R1=417.1 Ω
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