Asked by Allen
Two resistors when connected in series to a 120-V line use one-fourth the power that is used when they are connected in parallel. If one resistor is 4.8 kohms. what is the resistance of the other?
Answers
Answered by
MathMate
Power for resistors in series
= V²/(R1+R2)
Power for resistors in parallel
= V²/(1/(1/R1+1/R2))
= V²*(1/R1+1/R2)
Solve for R2.
= V²/(R1+R2)
Power for resistors in parallel
= V²/(1/(1/R1+1/R2))
= V²*(1/R1+1/R2)
Solve for R2.
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