Asked by stefani
You are playing volleyball. You hit the volleyball with an initial vertical velocity of 15 feet per second when it is 4 feet above the ground. Find how many seconds it takes to reach the maximum height, the maximum height reached, and the time the object is in the air.
Answers
Answered by
Henry
a. V = Vo + g*t
Tr = (V-Vo)/g = (0-15)/-32 = 0.469 s. To
reach max. Ht. = Rise time.
b. h = ho + Vo*t + 0.5g*t^2
h = 4 + 15*0.469 - 16*(0.469)^2=7.52Ft.
Above Gnd.
c. h = Vo*t + 0.5g*t^2 = 7.52 Ft.
0 + 16*T^2 = 7.52
T^2 = 0.469
Tf = 0.685 s. = Fall time.
T = Tr + Tf = 0.469 + 0.685 = 1.15 s. in
air.
Tr = (V-Vo)/g = (0-15)/-32 = 0.469 s. To
reach max. Ht. = Rise time.
b. h = ho + Vo*t + 0.5g*t^2
h = 4 + 15*0.469 - 16*(0.469)^2=7.52Ft.
Above Gnd.
c. h = Vo*t + 0.5g*t^2 = 7.52 Ft.
0 + 16*T^2 = 7.52
T^2 = 0.469
Tf = 0.685 s. = Fall time.
T = Tr + Tf = 0.469 + 0.685 = 1.15 s. in
air.
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