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A volleyball contains gas at the temperacture of 333 k has a volume of 12.5 liters. What will the temperature of the gas be if the volume is decreased to 7.0 L?
please show work.
Bot
answered
1 year ago
1 year ago
oobleck
answered
1 year ago
1 year ago
AAAaannndd the bot gets it wrong yet again!
Assuming constant pressure, PV=kT,
so V/T is constant. You want T such that
7/T = 12.5/333
T = 186.48 °K