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A volleyball is served at an angle of 35 degrees with an initial speed of 5 m/s. What is the maximum height reached by the ball?
Answers
Answered by
Henry
Vo = 5m/s[35o]
Yo = 5*sin35 = 2.87 m/s.
Y^2 = Yo^2 + 2g*h = 0
h = -Yo^2/2g = -(2.87)^2/-19.6 = 0.42 m
Yo = 5*sin35 = 2.87 m/s.
Y^2 = Yo^2 + 2g*h = 0
h = -Yo^2/2g = -(2.87)^2/-19.6 = 0.42 m
Answered by
joanna
A volleyball is served at an angle of 35 degrees with an initial speed of 5 m/s. What is the maximum height reached by the ball?
how find the maximum
how find the maximum
Answered by
ayen
compute for the range of the volleyball when it was served at an angle 50° to the horizontal with an initial velocity of 35 m/s.
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