Asked by mathemagiacian
The 23rd term in a certain geometric sequence is 16 and the 28th term in the sequence is 24. What is the 43rd term?
Answers
Answered by
Steve
d=(T28-T23)/(28-23) = (24-16)/5 = 8/5
T43 = T28+15d = 24 + 15(8/5) = 24+24 = 48
T43 = T28+15d = 24 + 15(8/5) = 24+24 = 48
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