Ask a New Question

Asked by Aliah

Find the eight term of the geometric sequence for which the first element is 3/8 and the common ratio is 2.
9 years ago

Answers

Answered by Reiny
a=3/8, r = 2

term8 = ar^7
= (3/8)(2^7)
= ....
9 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

Find the sixth term in the geometric sequence: sqrt3y^3, -3y^5, 3sqrt3y^7 Answer: -27y^13 2)... The 23rd term in a certain geometric sequence is 16 and the 28th term in the sequence is 24. What is... The 23rd term in a certain geometric sequence is 16 and the 28th term in the sequence is 24. What is... The 6th and 13th term of a geometric progression are 24 and 3/16 respectively.Find the sequence. Find a12 for the following geometric sequence. 1/32, 1/16, 1/8, How do I find the sum of a geometric series from 2 to infinity of -3/ (4^n) ? I need help with proofs in geometry. Can the sum of an infinite geometric sequence be negative? is the sequence 2,3,5,8,12 geometric? please explain why the first three terms of a geometric sequence are: t1; t2 and t3. if t2=t1-4 and t3=t2-9. determine...
Submit Your Answer

Question

Find the eight term of the geometric sequence for which the first element is 3/8 and the common ratio is 2.

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use