Asked by Aliah
Find the eight term of the geometric sequence for which the first element is 3/8 and the common ratio is 2.
Answers
Answered by
Reiny
a=3/8, r = 2
term8 = ar^7
= (3/8)(2^7)
= ....
term8 = ar^7
= (3/8)(2^7)
= ....
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