Asked by anonymous
the first three terms of a geometric sequence are: t1; t2 and t3. if t2=t1-4 and t3=t2-9. determine the values of t1; t2 an t3
Answers
Answered by
Damon
t1
r t1 = t1-4
r^2 t1 = (t1-4) -9 = t1 - 13
r (t1-4) = t1-13
r = (t1-13)/(t1-4) = (t1-4)/t1
so
t1^2 - 13 t1 = t1^2 -8 t1 + 16
-5 t1 = 16
t1 = -16/5 = -3.2
then r = (t1-4)/t1
= (-16/5 - 20/5)/-16/5 = 36/16 = 9/4
t2 = -16/5*9/4 = -7.2 = of course
t3 = -7.2*9/4 = -16.2 indeed -7.2-9
r t1 = t1-4
r^2 t1 = (t1-4) -9 = t1 - 13
r (t1-4) = t1-13
r = (t1-13)/(t1-4) = (t1-4)/t1
so
t1^2 - 13 t1 = t1^2 -8 t1 + 16
-5 t1 = 16
t1 = -16/5 = -3.2
then r = (t1-4)/t1
= (-16/5 - 20/5)/-16/5 = 36/16 = 9/4
t2 = -16/5*9/4 = -7.2 = of course
t3 = -7.2*9/4 = -16.2 indeed -7.2-9
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