Asked by Penny
1. The fourth and seventh terms of a geometric sequence are 6 and 384, respectively. What is the common ratio and the sixth term of the sequence?
2. The fifth and eight terms of a geometric sequence of real numbers are 7! and 8! respectively. What is the first term?
2. The fifth and eight terms of a geometric sequence of real numbers are 7! and 8! respectively. What is the first term?
Answers
Answered by
Steve
384/6 = 64
There are three terms, so r = 4
T6 = T4*r^2 = 6*16 = 96
r^3 = 8!/7! = 8
so, r=2
T1 = T5/r^4 = 7!/16 = 315
There are three terms, so r = 4
T6 = T4*r^2 = 6*16 = 96
r^3 = 8!/7! = 8
so, r=2
T1 = T5/r^4 = 7!/16 = 315
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