An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater. Show that when the time delay of an echo to the ocean floor below is 4 s, the depth of the water is 3060 m.
d=vt=1530ms x 2 =3060
not sure if i did it correct or missed a step..i should work on not seconding guessing myself
3 answers
your equation is correct. What does it represent? How does the "2" in your equation relate to the "4" in the problem?
distance traveled = time x speed
the 2 is half of 4s
the 2 is half of 4s
thank you, i was making sure i was correct before i responded back to steve.
i thought the 2 represented half of 4s, which is the delay of the echo
i thought the 2 represented half of 4s, which is the delay of the echo