Question
A body of mass 17.25kg rest on a smooth horizontal table. The coefficient of friction between the body and the table is 0.34. What is the horizontal frictional force that will make the body just slide.
Answers
Henry
Wb = m*g = 17.25kg * 9.8N/kg = 169 N. = Wt of body.
Fv = m*g = 169 N. = Force perpendicular to the table.
Fs = u*Fv = 0.34*169 = 57.5 N. = Force of static friction.
Fv = m*g = 169 N. = Force perpendicular to the table.
Fs = u*Fv = 0.34*169 = 57.5 N. = Force of static friction.