Asked by Moonblood
Body of mass 10 kg is at rest on a horizontal surface. A force of magnitude 10 N is applied to the body for 10 s. What is the final speed of the body?
Answers
Answered by
Damon
force = change in momentum/time
10 N = 10 kg *V / 10 s
V = 10 m/s
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or
F = m a
10 = 10 a
a = 1 m/s^2
v = a t
v = 1*10 = 10 m/s
10 N = 10 kg *V / 10 s
V = 10 m/s
=============
or
F = m a
10 = 10 a
a = 1 m/s^2
v = a t
v = 1*10 = 10 m/s
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