Asked by chimatiro
A body is dropped from rest at a height of 150 m and simultaneously another
body is dropped from rest from a point 100 m above the ground. What is the
difference between their heights after they have fallen for 3 seconds?
body is dropped from rest from a point 100 m above the ground. What is the
difference between their heights after they have fallen for 3 seconds?
Answers
Answered by
henry2,
1st Body:
h1 = ho - 0.5g*t^2 = 150 - 4.9*3^2 = 105.9 m. above gnd.
2nd Body:
h2 = ho - 0.5g*t^2 = 100 - 4.9*3^2 = 55.9 m. above gnd.
h1 - h2 = 105.9 - 55.9 = 50 m. = Difference between their hts.
h1 = ho - 0.5g*t^2 = 150 - 4.9*3^2 = 105.9 m. above gnd.
2nd Body:
h2 = ho - 0.5g*t^2 = 100 - 4.9*3^2 = 55.9 m. above gnd.
h1 - h2 = 105.9 - 55.9 = 50 m. = Difference between their hts.
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