The base of an isosceles triangle is four less than the sum of the lengths of the legs. If the perimeter of the triangle is 44, find the length of the three sides of the triangle.[ Only an algebraic solution will be accepted ]

Answer 1

let each of the equal sides be
let the base by y
then 2x + y = 44
y = 44-2x
So the base is 44 - 2x

"The base of an isosceles triangle is four less than the sum of the lengths of the legs" ---> 44 -2x = 2x-4
44 - 2x = 2x - 4
-4x = -48
x = 12

Each of the two legs is 12, and the base is 44-24 = 20