Asked by vincent
The base of an isosceles triangle is four less than the sum of the lengths of the legs. If the perimeter of the triangle is 44, find the length of the three sides of the triangle.[ Only an algebraic solution will be accepted ]
Answers
Answered by
Reiny
let each of the equal sides be
let the base by y
then 2x + y = 44
y = 44-2x
So the base is 44 - 2x
"The base of an isosceles triangle is four less than the sum of the lengths of the legs" ---> 44 -2x = 2x-4
44 - 2x = 2x - 4
-4x = -48
x = 12
Each of the two legs is 12, and the base is 44-24 = 20
let the base by y
then 2x + y = 44
y = 44-2x
So the base is 44 - 2x
"The base of an isosceles triangle is four less than the sum of the lengths of the legs" ---> 44 -2x = 2x-4
44 - 2x = 2x - 4
-4x = -48
x = 12
Each of the two legs is 12, and the base is 44-24 = 20
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.