Asked by Chris
Determine the quadratic function f whose vertex is (3,-2) and passes through(1,6)
f(x) = ax^2 + bx + c
f(x) = ax^2 + bx + c
Answers
Answered by
Steve
from the vertex, we know
f(x) = a(x-3)^2 - 2
Since f(1) = 6,
6 = a(1-3)^2 - 2
a = 2
f(x) = 2(x-3)^2 - 2
= 2x^2 - 12x + 16
f(x) = a(x-3)^2 - 2
Since f(1) = 6,
6 = a(1-3)^2 - 2
a = 2
f(x) = 2(x-3)^2 - 2
= 2x^2 - 12x + 16
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