Asked by gal
Determine the quadratic function of the following:
Congruent to y=-12x2; opens up; vertex at (-3,2)
Congruent to y=-12x2; opens up; vertex at (-3,2)
Answers
Answered by
Steve
since y = -12x^2 has vertex at (0,0) and opens down, your function is reflected in the x-axis, shifted left 3 and up 2, so it is
12(x+3)^2 + 2
12(x+3)^2 + 2
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