Question
A dragster and driver together have mass 929.4 kg. The dragster, starting from rest, attains a speed of 26.5 m/s in 0.55s.
What is the size of the average force on the dragster during this time interval? Answer in units of N.
What is the size of the average force on the dragster during this time interval? Answer in units of N.
Answers
a=(V-Vo)/t = (26.5-0)/0.55 = 48.2 m/s^2.
F = m*a = 929.4 * 48.2 = 44,780 N.
F = m*a = 929.4 * 48.2 = 44,780 N.
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