A 600 kg dragster accelerates from rest to a final speed of 120 m/s in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is its average power output in watts and horsepower if this takes 7.30 s?

Answer 1

ma=mv²/2s =600•120²/2•400 =10800
P=W/t=[F+F(fr)]s/t = {10800+1200}•400/7.3 = 6.58•10⁵W =894 hp

Answer 2

yuh just do it we all dumb