Asked by deepu
                calculate the volume occupied by 5.25 gram of nitrogen at 26 degree Celsius and 74.2 cm of pressure
            
            
        Answers
                    Answered by
            MathMate
            
    Assuming 74.2 cm of pressure refers to the mercury column.
Under standard temperature and pressure (273.15°K, 100 kPa=760.06 mmHg),
the gas constant is:
62.364 L mmHg K−1 mol−1
molecular mass of N2=2*14.0067=28.0134
So
volume occupied by 5.25 gram of nitrogen at 26 degree Celsius and 74.2 cm of pressure
=62.364/742*(273.15+26)*(5.25/28.0134)
=4.7 litres
    
Under standard temperature and pressure (273.15°K, 100 kPa=760.06 mmHg),
the gas constant is:
62.364 L mmHg K−1 mol−1
molecular mass of N2=2*14.0067=28.0134
So
volume occupied by 5.25 gram of nitrogen at 26 degree Celsius and 74.2 cm of pressure
=62.364/742*(273.15+26)*(5.25/28.0134)
=4.7 litres
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