Asked by deepu
calculate the volume occupied by 5.25 gram of nitrogen at 26 degree Celsius and 74.2 cm of pressure
Answers
Answered by
MathMate
Assuming 74.2 cm of pressure refers to the mercury column.
Under standard temperature and pressure (273.15°K, 100 kPa=760.06 mmHg),
the gas constant is:
62.364 L mmHg K−1 mol−1
molecular mass of N2=2*14.0067=28.0134
So
volume occupied by 5.25 gram of nitrogen at 26 degree Celsius and 74.2 cm of pressure
=62.364/742*(273.15+26)*(5.25/28.0134)
=4.7 litres
Under standard temperature and pressure (273.15°K, 100 kPa=760.06 mmHg),
the gas constant is:
62.364 L mmHg K−1 mol−1
molecular mass of N2=2*14.0067=28.0134
So
volume occupied by 5.25 gram of nitrogen at 26 degree Celsius and 74.2 cm of pressure
=62.364/742*(273.15+26)*(5.25/28.0134)
=4.7 litres
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