Asked by Shruti Singh Parihar
Calculate the volume occupied by 10^22 molecules of a gas at 300K and 760mm pressure.
Step by step explanation please.
Step by step explanation please.
Answers
Answered by
oobleck
since PV=kT and 6.02*10^23 occupies 22.4L at STP, you want V such that
760V/300 = 760*(10^22/6.02*10^23)*22.4/273
V = 0.4L
760V/300 = 760*(10^22/6.02*10^23)*22.4/273
V = 0.4L
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