Asked by Nusaiba
                1.Calculate the volume occupied by 3.2g of oxygen at 300K and 100KNm^-2.(R=8.3J/mol/K,Oxygen =16).
2.Calculate the volume occupied by 0.125mol of Oxygen at 27°C and a pressure of 2.02×10^5Nm^2.(1mole of gas occupies 22.4dm^3 at Standard temperature and pressure,where standard temperature is =1.01×10^5Nm^-2)
            
            
        2.Calculate the volume occupied by 0.125mol of Oxygen at 27°C and a pressure of 2.02×10^5Nm^2.(1mole of gas occupies 22.4dm^3 at Standard temperature and pressure,where standard temperature is =1.01×10^5Nm^-2)
Answers
                    Answered by
            DrBob222
            
    1. 100 kN/m^2 = 0.998 atm, R = 0.08206 L*atm/mol*K , n = 3.2/32
PV = nRT
0.998*V = (3.2/32)*0.08206 L*atm/mol*K * 300 K
Solve for V in liters
For 2. You surely don't mean <B> standard temperature is =1.01×10^5Nm^-2) </B>
    
PV = nRT
0.998*V = (3.2/32)*0.08206 L*atm/mol*K * 300 K
Solve for V in liters
For 2. You surely don't mean <B> standard temperature is =1.01×10^5Nm^-2) </B>
                    Answered by
            Anonymous
            
    Can someone solve number 2 question please
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.