Asked by Katie
Can someone please explain this to me?!
Please! Thank you!
How much (in kilograms) ethylene glycol antifreeze (C2H6O2)(molar mass 62.02 g/mol) has to be added to 14.4 kg of water to get a mixture that freezes at -15.5 degrees C. For water Kf = 1.86 degrees C kg/mol
Please! Thank you!
How much (in kilograms) ethylene glycol antifreeze (C2H6O2)(molar mass 62.02 g/mol) has to be added to 14.4 kg of water to get a mixture that freezes at -15.5 degrees C. For water Kf = 1.86 degrees C kg/mol
Answers
Answered by
DrBob222
To make it easy to type let's call ethylene glycol just eth.
delta T = Kf*m
You know delta T (15.5) and you know Kf, solve for molality eth.
m = mols/kg solvent
You know m eth and kg solvent, solve for mols eth.
mols = grams/molar mass. You know mols eth and molar mass eth, solve for grams eth.
delta T = Kf*m
You know delta T (15.5) and you know Kf, solve for molality eth.
m = mols/kg solvent
You know m eth and kg solvent, solve for mols eth.
mols = grams/molar mass. You know mols eth and molar mass eth, solve for grams eth.
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