Asked by Jim

Initially, a spring-mass system completes 20.0 vibrations in 5.0 seconds, with a 2.0 cm amplitude.
The same mass is pulled 5.0 cm away from the equilibrium position, then released. What will the frequency be?

Answers

Answered by Elena
f=ω/2π =sqrt(k/m)/ 2π
f=N/t=20/5=4 Hz
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