Asked by Jim
Initially, a spring-mass system completes 20.0 vibrations in 5.0 seconds, with a 2.0 cm amplitude.
The same mass is pulled 5.0 cm away from the equilibrium position, then released. What will the frequency be?
The same mass is pulled 5.0 cm away from the equilibrium position, then released. What will the frequency be?
Answers
Answered by
Elena
f=ω/2π =sqrt(k/m)/ 2π
f=N/t=20/5=4 Hz
f=N/t=20/5=4 Hz
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