Asked by Jim
                Initially, a spring-mass system completes 20.0 vibrations in 5.0 seconds, with a 2.0 cm amplitude. 
The same mass is pulled 5.0 cm away from the equilibrium position, then released. What will the frequency be?
            
        The same mass is pulled 5.0 cm away from the equilibrium position, then released. What will the frequency be?
Answers
                    Answered by
            Elena
            
    f=ω/2π =sqrt(k/m)/ 2π
f=N/t=20/5=4 Hz
    
f=N/t=20/5=4 Hz
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