Asked by Wrenn
A mass-on-a-spring system has
m = 54 kg and k = 225 N/m.
The mass is pulled a distance 0.25 m from its equilibrium position and then released.
(a) What is the maximum acceleration of the mass?
My work: F=ma -kx=ma
(225)(.25)=(54kg)(a)
solve for a. a=1.04 m/s^2. this is correct
(b) What is its maximum velocity?
I'm not really sure how to start this. I know that max velocity is equal to amplitude times sqrt(k/m), but I do not know the amplitude. Please help.
m = 54 kg and k = 225 N/m.
The mass is pulled a distance 0.25 m from its equilibrium position and then released.
(a) What is the maximum acceleration of the mass?
My work: F=ma -kx=ma
(225)(.25)=(54kg)(a)
solve for a. a=1.04 m/s^2. this is correct
(b) What is its maximum velocity?
I'm not really sure how to start this. I know that max velocity is equal to amplitude times sqrt(k/m), but I do not know the amplitude. Please help.
Answers
Answered by
Madi
The amplitude is the 0.25m distance you pull the spring, plug that into the equation you said and it should work, good luck!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.