Calculate the [H], [OH], pH and the pOH of this solution; 0.0025 M NaOH

Answer 1

To me its like this;

the [OH] is 0.0025, so we can calculate [H] using [H][OH] = 1e14 and rearranging for [H] gives 1e14/[OH]

with [H], we can find pH = -log[H]. Then use pH to find pOH using pH + pOH = 14.

hope that helps.