Asked by tony
Find all values of ¸ in [0°, 360°) that satisfy the equation.
2 sin 2θ - √(3) = 0
2 sin 2θ - √(3) = 0
Answers
Answered by
Steve
2sin2θ = √3
sin2θ = √3/2
sin(x) is positive in QI,QII
2θ = 60°,120°,...
we need to go for two periods because we're dealing with 2θ. That gives us
θ = 30°,60°,210°,240°
sin2θ = √3/2
sin(x) is positive in QI,QII
2θ = 60°,120°,...
we need to go for two periods because we're dealing with 2θ. That gives us
θ = 30°,60°,210°,240°
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