Question
What mass of KOH is required to neutralize 200mL of 3.16 M HNO3?
Answers
bonjo
find the mole for HNO3 using n = MV where M is the molarity and V is the volume in Liters.
then use the balance equation;
KOH + HNO3 --> KNO3 + H2O
the reaction is 1:1 so the mole you calculated for HNO3 is also the mole for KOH.
i.e. mole KOH = mole HNO3.
then convert the mole to mass using the molar mass of KOH (obtain from periodic table) to get the mass for KOH.
hope that helps...
then use the balance equation;
KOH + HNO3 --> KNO3 + H2O
the reaction is 1:1 so the mole you calculated for HNO3 is also the mole for KOH.
i.e. mole KOH = mole HNO3.
then convert the mole to mass using the molar mass of KOH (obtain from periodic table) to get the mass for KOH.
hope that helps...